Question

2Mr (MgO) = 5Mr (CH4) =

Answer 1

Ответ:

2Mr(MgO)=2×24+16=80г/моль

5Mr(CH4)=5×12+4=80г/моль

Answer 2

It looks like you're trying to equate the molar masses of two different compounds, magnesium oxide (MgO) and methane (CH4). The equation you provided, "2Mr (MgO) = 5Mr (CH4)," suggests that the molar mass of magnesium oxide is twice the molar mass of methane. However, this equation is not accurate.

Let's calculate the molar masses of both compounds to verify:

1. Magnesium Oxide (MgO):

• Molar mass of magnesium (Mg): ~24.31 g/mol
• Molar mass of oxygen (O): ~16.00 g/mol
• Molar mass of MgO = Molar mass of Mg + Molar mass of O = 24.31 g/mol + 16.00 g/mol = 40.31 g/mol

2. Methane (CH4):

• Molar mass of carbon (C): ~12.01 g/mol
• Molar mass of hydrogen (H): ~1.01 g/mol
• Molar mass of CH4 = Molar mass of C + 4 * Molar mass of H = 12.01 g/mol + 4 * 1.01 g/mol = 16.05 g/mol

As you can see, the molar mass of magnesium oxide (MgO) is not twice the molar mass of methane (CH4). In fact, the molar mass of magnesium oxide is greater than the molar mass of methane.

If you have a different equation or question in mind, please provide more information, and I'd be happy to assist you further.

Answer 3

It seems like you're trying to balance a chemical equation involving magnesium oxide (MgO) and methane (CH4). The notation you've used, "Mr," is not standard in chemistry. The correct notation for balancing chemical equations involves using coefficients to balance the number of atoms on both sides of the equation.

The balanced chemical equation for the reaction between magnesium oxide and methane would be:

2 MgO + 5 CH4 → 2 Mg + 5 CO2 + 4 H2O

This equation shows that 2 molecules of magnesium oxide react with 5 molecules of methane to produce 2 molecules of magnesium, 5 molecules of carbon dioxide, and 4 molecules of water. The coefficients (numbers in front of the chemical formulas) are used to balance the equation and ensure that the number of atoms of each element is the same on both sides of the equation.