Question

А14С3-СН4-СН3Br-C2H6-C2H4-C2H4Br2

Answer 1

Al4C3 + 12H2O -> 3CH4 + 4Al(OH)3
CH4 + Br2 -> HBr + CH3Br
2CH3Br + 2Na -> 2NaBr + CH3-CH3
CH3-CH3 -> CH2=CH2 + H2
CH2=CH2 + Br2 -> CH2Br-CH2Br

Answer 2

The compound sequence you provided appears to be a series of organic compounds. Each component represents a different chemical compound. Here's a breakdown of the compounds in the sequence you mentioned:

1. A14C3: This compound does not match any known organic compound. The "A14" portion doesn't represent any recognized organic functional group, so it's unclear what this compound might be.

2. СН4: This compound represents methane, which is the simplest hydrocarbon with one carbon atom and four hydrogen atoms. Its chemical formula is CH4.

3. СН3Br: This compound represents methyl bromide, which is an organic compound consisting of a methyl group (CH3) bonded to a bromine atom (Br). Its chemical formula is CH3Br.

4. C2H6: This compound represents ethane, which is a hydrocarbon with two carbon atoms and six hydrogen atoms. Its chemical formula is C2H6.

5. C2H4: This compound represents ethene, also known as ethylene, which is a hydrocarbon with two carbon atoms and four hydrogen atoms. Its chemical formula is C2H4.

6. C2H4Br2: This compound represents 1,2-dibromoethane, which is an organic compound with two bromine atoms attached to a ethylene group. Its chemical formula is C2H4Br2.

Please note that the compound you mentioned at the beginning, A14C3, is not recognized as a valid organic compound based on the current information available to me. It's possible that it could be a typo or an unknown compound.