Question

Al → Al2S3 →Al(OH)3 →Al2(SO4)3​

Answer 1

Ответ:

Al+S=Al2S3

Al2S3+H2O=Al(OH)3+H2S

Al(OH)3+H2SO4=Al2(SO4)3+H2O

Answer 2

The series of chemical reactions you've provided seems to describe the transformation of aluminum (Al) through several reactions to form various compounds. Let's break down each step:

1. Al → Al2S3: In this step, aluminum (Al) reacts with sulfur (S) to form aluminum sulfide (Al2S3). The balanced chemical equation for this reaction is:

   2 Al + 3 S → Al2S3

2. Al2S3 → Al(OH)3: In this step, aluminum sulfide (Al2S3) reacts with water (H2O) to form aluminum hydroxide (Al(OH)3). The balanced chemical equation for this reaction is:

   Al2S3 + 6 H2O → 2 Al(OH)3 + 3 H2S

3. Al(OH)3 → Al2(SO4)3: In this step, aluminum hydroxide (Al(OH)3) reacts with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3). The balanced chemical equation for this reaction is:

   2 Al(OH)3 + 3 H2SO4 → Al2(SO4)3 + 6 H2O

So, the overall sequence of reactions is as follows: Al → Al2S3 → Al(OH)3 → Al2(SO4)3

These reactions show how aluminum can undergo various chemical transformations to produce different compounds under the appropriate conditions and reactants.