
KMnO4 + KNO2 + KOH → K2MnO4+ KNO3 + H2O


Ответы на вопрос

Ответ:
2KMnO4 + KNO2 + 2KOH → 2K2MnO4 + KNO3 + H2O
Объяснение:



The chemical equation you've provided appears to be unbalanced. Let's balance it:
The given equation is:
KMnO4 + KNO2 + KOH → K2MnO4 + KNO3 + H2O
First, let's write down the equation with the correct chemical formulas:
2KMnO4 + 2KNO2 + 2KOH → K2MnO4 + 2KNO3 + H2O
Now, let's balance the equation:
On the left side, we have 2 potassium atoms (K) from KMnO4, 2 from KNO2, and 2 from KOH. So, we have a total of 2 + 2 + 2 = 6 potassium atoms on the left side.
On the right side, we have 2 potassium atoms (K) from K2MnO4 and 2 from KNO3. So, we have a total of 2 + 2 = 4 potassium atoms on the right side.
To balance the potassium atoms, we need to multiply K2MnO4 on the right side by 3 to get 6 potassium atoms:
2KMnO4 + 2KNO2 + 2KOH → 3K2MnO4 + 2KNO3 + H2O
Now, let's balance the other elements:
Manganese (Mn) atoms: 2 on the left and 3 on the right. We can balance this by changing the coefficient of KMnO4 on the left to 3:
3KMnO4 + 2KNO2 + 2KOH → 3K2MnO4 + 2KNO3 + H2O
Now, let's balance the nitrogen (N) atoms:
Nitrogen (N) atoms: 2 on the left and 5 on the right. We can balance this by changing the coefficient of KNO3 on the right to 2:
3KMnO4 + 2KNO2 + 2KOH → 3K2MnO4 + 4KNO3 + H2O
Now, let's balance the oxygen (O) atoms:
Oxygen (O) atoms:
Left side: 12 from KMnO4, 2 from KNO2, and 2 from KOH for a total of 12 + 2 + 2 = 16 oxygen atoms.
Right side: 12 from K2MnO4, 12 from KNO3, and 1 from H2O for a total of 12 + 12 + 1 = 25 oxygen atoms.
To balance the oxygen atoms, we need to adjust the coefficient of H2O on the left side to 9:
3KMnO4 + 2KNO2 + 2KOH → 3K2MnO4 + 4KNO3 + 9H2O
Now, all the elements are balanced. The balanced equation is:
3KMnO4 + 2KNO2 + 2KOH → 3K2MnO4 + 4KNO3 + 9H2O


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