Question

Azot (IV)-oksidning vodorodga va havoga nisbatan zichligini aniqlang.​

Answer 1

Ответ:

0хххххххххх как юююююююююююююююююю

Answer 2

Azot (IV) oksidi va suvning orasidagi nisbatni hisoblash uchun, quyidagi formulani foydalanamiz:

$\text{Nisbat} = \frac{\text{Massa nitrogen oksidi (N2O4)}}{\text{Massa suv (H2O)}}$

N2O4 va H2O molekulalarining massalari:

• Azot (IV) oksidi (N2O4) molekulasi yalpi massa bo'yicha:

  • Nitrogen (N) atomlarining massasi: 14.007 amu
  • Oxygen (O) atomlarining massasi: 15.9994 amu (quyidagi oksidatsiya holatida: $+4$) Jami: $2 \times 14.007 \, \text{amu} + 4 \times 15.9994 \, \text{amu} = 92.0278 \, \text{amu}$

• Suv (H2O) molekulasi yalpi massa bo'yicha:

  • Hidrogen (H) atomlarining massasi: 1.00784 amu
  • Oxygen (O) atomlarining massasi: 15.9994 amu (quyidagi oksidatsiya holatida: $+2$) Jami: $2 \times 1.00784 \, \text{amu} + 15.9994 \, \text{amu} = 18.01528 \, \text{amu}$

Nisbatni hisoblash:

$\text{Nisbat} = \frac{92.0278 \, \text{amu}}{18.01528 \, \text{amu}} \approx 5.105$

Shu sababli, azot (IV) oksidi (N2O4) va suv (H2O) orasidagi nisbat 5.105 ga tengdir.