Question

(NH4)2Cr2O7=Cr2O3+N2+H2O ОВР ​

Answer 1

Ответ:

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Answer 2

The given chemical equation appears to be unbalanced. To balance it, you can follow these steps:

1. Count the number of atoms of each element on both sides of the equation.

On the left side:

• Chromium (Cr): 2 atoms (in (NH4)2Cr2O7)
• Nitrogen (N): 2 atoms (in (NH4)2Cr2O7)
• Hydrogen (H): 8 atoms (in (NH4)2Cr2O7)
• Oxygen (O): 7 atoms (in (NH4)2Cr2O7)

On the right side:

• Chromium (Cr): 2 atoms (in Cr2O3)
• Nitrogen (N): 2 atoms (in N2)
• Hydrogen (H): 2 atoms (in H2O)
• Oxygen (O): 3 atoms (in Cr2O3 and H2O)

2. Now, you need to balance the equation by adjusting the coefficients in front of each compound to make the number of atoms of each element the same on both sides.

Let's start by balancing Chromium (Cr):

• There are 2 Cr atoms on both sides, so Cr is already balanced.

Next, balance Nitrogen (N):

• There are 2 N atoms on the left and 2 N atoms on the right, so N is already balanced.

Now, balance Hydrogen (H):

• There are 8 H atoms on the left and 2 H atoms on the right. To balance H, you can place a coefficient of 4 in front of H2O on the right side.

Now, balance Oxygen (O):

• There are 7 O atoms on the left and 3 O atoms on the right. To balance O, you can place a coefficient of 7 in front of Cr2O3 on the right side.

The balanced equation is:

(NH4)2Cr2O7 → Cr2O3 + N2 + 4H2O

Now, all the elements are balanced on both sides of the equation.