Question

Расставьте коэффициенты в уравнениях методом электронного баланса: 1)Li + O2} Li2O 2)CuO + NH3 }Cu + N2 + H2O 3)CH4 + O2 } CO2 + H2O *4)Cu + H2SO4 (k) } CuSO4 + SO2 + H2O Помогите с химией пожалуйста!

Answer 1

Ответ:

1) 4Li+O2= 2Li2O

2) 3CuO+2NH3=3Cu+N2+3H2O

3)CH4+2O2=CO2+3H2O

4)Cu+2H2SO4=CuSO4+SO2+2H2O

Answer 2

Balancing Chemical Equations

Balancing chemical equations involves adjusting the coefficients of the reactants and products to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the given equations using the method of electronic balancing:

1) Li + O2 → Li2O

To balance this equation, we need to ensure that the number of lithium (Li) and oxygen (O) atoms is the same on both sides.

Let's start by balancing the oxygen atoms. Since there are two oxygen atoms in Li2O, we need to put a coefficient of 2 in front of O2:

Li + 2O2 → Li2O

Now, let's balance the lithium atoms. There are two lithium atoms on the left side, so we need to put a coefficient of 2 in front of Li:

2Li + 2O2 → 2Li2O

The balanced equation is: 2Li + 2O2 → 2Li2O.

2) CuO + NH3 → Cu + N2 + H2O

To balance this equation, we need to ensure that the number of copper (Cu), nitrogen (N), and hydrogen (H) atoms is the same on both sides.

Let's start by balancing the nitrogen atoms. There are two nitrogen atoms on the right side, so we need to put a coefficient of 2 in front of NH3:

CuO + 2NH3 → Cu + N2 + H2O

Now, let's balance the hydrogen atoms. There are six hydrogen atoms on the right side, so we need to put a coefficient of 3 in front of H2O:

CuO + 2NH3 → Cu + N2 + 3H2O

Finally, let's balance the oxygen atoms. There are three oxygen atoms on the left side (from CuO) and six oxygen atoms on the right side (from H2O). To balance them, we need to put a coefficient of 3 in front of CuO:

3CuO + 2NH3 → Cu + N2 + 3H2O

The balanced equation is: 3CuO + 2NH3 → Cu + N2 + 3H2O.

3) CH4 + O2 → CO2 + H2O

To balance this equation, we need to ensure that the number of carbon (C), hydrogen (H), and oxygen (O) atoms is the same on both sides.

Let's start by balancing the carbon atoms. There is one carbon atom on the left side, so we need to put a coefficient of 1 in front of CO2:

CH4 + O2 → 1CO2 + H2O

Now, let's balance the hydrogen atoms. There are four hydrogen atoms on the left side (from CH4) and two hydrogen atoms on the right side (from H2O). To balance them, we need to put a coefficient of 2 in front of H2O:

CH4 + O2 → 1CO2 + 2H2O

Finally, let's balance the oxygen atoms. There are two oxygen atoms on the left side (from O2) and three oxygen atoms on the right side (from CO2 and H2O). To balance them, we need to put a coefficient of 2 in front of O2:

CH4 + 2O2 → 1CO2 + 2H2O

The balanced equation is: **CH4 + 2O