Question

KClO3→KCl+O2 2) Na+Cl2→NaCl 3) Mg + O2 → MgO 4) H2O+SO3→H2SO4 5) Al+S→Al2S3 6) H2O2→H2O+O2 7) Rb2O+H2O→RbOH 8) Ba+O2→BaO

Answer 1

Ответ:

1. 2KClO3→2KCl+3O2
2. 2Na+Cl2→2NaCl
3. 2Mg + O2 → 2MgO
4. H2O+SO3→H2SO4
5. 2Al+3S→Al2S3
6. H2O2→H2O+O2
7. Rb2O+H2O→2RbOH
8. 2Ba+O2→2BaO

Answer 2

I will answer in detail. To balance the chemical equations, we need to make sure that the number of atoms of each element is the same on both sides of the arrow. We can do this by adding coefficients (whole numbers) in front of the formulas, but we cannot change the subscripts (small numbers) inside the formulas. Here are the balanced equations and the types of reactions:

1) KClO3 → KCl + O2

This is a decomposition reaction, where a compound breaks down into simpler substances. To balance it, we need to have 3 oxygen atoms on both sides, so we add a coefficient of 2 in front of KClO3 and a coefficient of 3 in front of O2. The balanced equation is:

2 KClO3 → 2 KCl + 3 O2

2) Na + Cl2 → NaCl

This is a synthesis reaction, where two or more elements combine to form a compound. To balance it, we need to have 2 chlorine atoms on both sides, so we add a coefficient of 2 in front of Na and NaCl. The balanced equation is:

2 Na + Cl2 → 2 NaCl

3) Mg + O2 → MgO

This is also a synthesis reaction, where magnesium and oxygen form magnesium oxide. To balance it, we need to have 2 oxygen atoms on both sides, so we add a coefficient of 2 in front of Mg and MgO. The balanced equation is:

2 Mg + O2 → 2 MgO

4) H2O + SO3 → H2SO4

This is a synthesis reaction, where water and sulfur trioxide form sulfuric acid. To balance it, we need to have 2 hydrogen atoms and 4 oxygen atoms on both sides, so we add a coefficient of 2 in front of H2O and H2SO4. The balanced equation is:

2 H2O + SO3 → H2SO4

5) Al + S → Al2S3

This is a synthesis reaction, where aluminum and sulfur form aluminum sulfide. To balance it, we need to have 2 aluminum atoms and 3 sulfur atoms on both sides, so we add a coefficient of 2 in front of Al and a coefficient of 3 in front of S. The balanced equation is:

2 Al + 3 S → Al2S3

6) H2O2 → H2O + O2

This is a decomposition reaction, where hydrogen peroxide breaks down into water and oxygen. To balance it, we need to have 2 hydrogen atoms and 2 oxygen atoms on both sides, so we add a coefficient of 2 in front of H2O and O2. The balanced equation is:

H2O2 → 2 H2O + O2

7) Rb2O + H2O → RbOH

This is a synthesis reaction, where rubidium oxide and water form rubidium hydroxide. To balance it, we need to have 2 rubidium atoms and 2 oxygen atoms on both sides, so we add a coefficient of 2 in front of RbOH. The balanced equation is:

Rb2O + H2O → 2 RbOH

8) Ba + O2 → BaO

This is a synthesis reaction, where barium and oxygen form barium oxide. To balance it, we need to have 2 oxygen atoms on both sides, so we add a coefficient of 2 in front of Ba and BaO. The balanced equation is:

2 Ba + O2 → 2 BaO

I hope this helps you understand how to balance chemical equations and identify the types of reactions. If you want to learn more about this topic, you can check out some of the web search results I found for you . You can also see some examples of how to balance equations in different languages . Have a nice day!