Question

Скласти молекулярне, йонно-молекулярне та скорочене йонне рівняння між калій гідроксидом та сульфатною кислотою. Хто знає, не проходьте мимо, допоможіть) ​

Answer 1

Відповідь:

Молекулярне: 2KOH+H2SO4=K2SO4 + 2H2O

Повне йонне: 2K(+) + 2OH(-) + 2H(+) + SO4(2-) = 2K(+) + SO4(2-) + 2H2O

Скорочене йонне: H(+) + OH(-) = H2O

Answer 2

Molecular Equation:

The molecular equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) can be written as follows:

KOH + H2SO4 → K2SO4 + H2O [[1]]

Ionic-Molecular Equation:

To write the ionic-molecular equation, we need to break down the reactants and products into their respective ions. Potassium hydroxide dissociates into potassium ions (K+) and hydroxide ions (OH-), while sulfuric acid dissociates into hydrogen ions (H+) and sulfate ions (SO4^2-). The balanced ionic-molecular equation is as follows:

2K+ (aq) + 2OH- (aq) + H+ (aq) + SO4^2- (aq) → K2SO4 (aq) + 2H2O (l) [[1]]

Net Ionic Equation:

The net ionic equation is obtained by removing the spectator ions, which are ions that do not participate in the actual chemical reaction. In this case, the spectator ions are potassium ions (K+) and sulfate ions (SO4^2-). The net ionic equation is as follows:

2OH- (aq) + H+ (aq) → 2H2O (l) [[1]]

This net ionic equation represents the actual chemical reaction between potassium hydroxide and sulfuric acid, where hydroxide ions react with hydrogen ions to form water.

I hope this helps! Let me know if you have any further questions.