Question

Дана схема превращений: Cu(NO3)2 → X → HNO3 → Mg(NO3)2 Na2SO3 → X → SO3 → Na2SO4 Напишите молекулярные уравнения реакций, с помощью которых можно осуществить указанные превращения. Для третьего превращения составьте сокращенное ионное уравнение.

Answer 1

1.) 2Cu(NO₃)₂ =(t°) 2CuO + 4NO₂ + O₂

2.) 2NO₂ + H₂O = HNO₃ + HNO₂

3.) 2HNO₃ + MgCO₃ = Mg(NO₃)₂ + H₂O + CO₂

2H⁺ + 2NO₃⁻ + Mg²⁺ + CO₃²⁻ = Mg²⁺ + 2NO₃⁻ + H₂O + CO₂

4.) Na₂SO₃ + 2HCl = 2NaCl + H₂O + SO₂

5.) 2SO₂ + O₂ =(t°, кат.) 2SO₃

6.) SO₃ + 2NaOH = Na₂SO₄ + H₂O

Answer 2

Molecular Equations for the Given Transformations:

1. Cu(NO3)2 → X → HNO3 → Mg(NO3)2

- Cu(NO3)2 + X → HNO3 + Mg(NO3)2

2. Mg(NO3)2 + Na2SO3 → X → SO3 → Na2SO4

- Mg(NO3)2 + Na2SO3 + X → SO3 + Na2SO4

Ion Equation for the Third Transformation:

The third transformation involves the reaction between HNO3 and Mg(NO3)2 to produce Mg(NO3)2. The ion equation for this reaction can be written as:

H+ + NO3- + Mg2+ + 2NO3- → Mg2+ + 2NO3- + H+ + NO3-

Simplifying the equation, we get:

2H+ + 2NO3- + Mg2+ → Mg2+ + 2NO3- + H+ + NO3-

The spectator ions (Mg2+ and NO3-) are the same on both sides of the equation, so they can be canceled out:

2H+ → H+

The simplified ion equation for the third transformation is:

2H+ → H+

Please note that the ion equation provided is a simplified representation of the reaction and does not include all the species present in the reaction.