Question

K2Fe2O4 степінь окиснення. будь ласка..​

Answer 1

K2Fe2O4.

Степень окисления калия "+1".

Степень окисления кислорода "-2".

2 + 2x - 8 = 0.

2x = 6.

x = 3.

Ответ: Степень окисления железа "+3".

Answer 2

K2Fe2O4, also known as potassium ferrate(IV), is a compound that contains potassium (K) and iron (Fe) ions. To determine the oxidation state of each element in K2Fe2O4, we need to consider the overall charge of the compound and the known oxidation states of the other elements involved.

In K2Fe2O4, the potassium ion (K+) has a known oxidation state of +1. Since there are two potassium ions in the compound, the total charge contributed by potassium is +2.

To determine the oxidation state of iron (Fe), we can assign x as the oxidation state of Fe. Since there are two iron ions in the compound, the total charge contributed by iron is 2x.

The overall charge of the compound is -2, as indicated by the subscript 4 in the formula. This means that the sum of the charges contributed by potassium and iron must equal -2.

Based on this information, we can set up the following equation:

2(+1) + 2x + 4(-2) = -2

Simplifying the equation, we have:

2 + 2x - 8 = -2

Combining like terms, we get:

2x - 6 = -2

Adding 6 to both sides of the equation, we have:

2x = 4

Dividing both sides of the equation by 2, we find:

x = 2

Therefore, the oxidation state of iron (Fe) in K2Fe2O4 is +2.