Question

Задание 5. Определите обьем кислорода, необходимого для окисления 20 л оксида углерода (II) до оксида углерода (IV) по уравнению: 2СО+О2=2СО2 РЕШИТЕ ПОЖАЛУЙСТА, ДАЮ 50 БАЛЛОВ ​

Answer 1

Ответ:9,5л.

Объяснение:

2СО+О2=2СО2 объем (СО)=20*0,95=19л Так как все вещества - газы: объем(О2)=1/2объема(СО)=9,5л.

Answer 2

To determine the volume of oxygen required to oxidize 20 L of carbon monoxide (CO) to carbon dioxide (CO2) according to the equation 2CO + O2 = 2CO2, we need to use the stoichiometry of the reaction.

The balanced equation tells us that 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2. Therefore, the stoichiometric ratio is 2:1:2 for CO:O2:CO2.

To find the volume of oxygen required, we can use the following steps:

1. Convert the given volume of CO to moles using the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Since the pressure and temperature are not given, we can assume standard conditions (1 atm and 273 K).

Using the molar volume of an ideal gas at standard conditions (22.4 L/mol), we can calculate the number of moles of CO: 20 L CO * (1 mol CO / 22.4 L CO) = 0.893 moles CO.

2. Apply the stoichiometric ratio to determine the number of moles of O2 required. Since the ratio is 2:1, we need half the number of moles of CO: 0.893 moles CO * (1/2) = 0.4465 moles O2.

3. Convert the moles of O2 to volume using the molar volume of an ideal gas at standard conditions: 0.4465 moles O2 * 22.4 L/mol = 9.99 L O2.

Therefore, the volume of oxygen required to oxidize 20 L of carbon monoxide (II) to carbon dioxide (IV) is approximately 9.99 L O2.

Please note that the calculations assume ideal gas behavior and standard conditions.