Question

5.27. Массовая доля метанола в водном растворе ранна 40 %. Определите объемную долю (в процентах) метанола. Плотность метанола равна 0,8 г/мл, воды г/мл. Изменением объемов при смешивании пренебречь.​

Answer 1

Ответ:

Объяснение:

Держи,внизу.

Answer 2

Calculation of Volume Fraction of Methanol in Water Solution

To determine the volume fraction of methanol in a water solution, we can use the given mass fraction of methanol and the densities of methanol and water.

Given: - Mass fraction of methanol in the solution: 40% - Density of methanol: 0.8 g/mL - Density of water: 1 g/mL (approximate value)

To calculate the volume fraction of methanol, we need to convert the mass fraction to a volume fraction. We can assume that the volume of the solution remains constant when the components are mixed.

Let's assume we have 100 mL of the solution. Since the mass fraction of methanol is 40%, we have 40 g of methanol and 60 g of water in the solution.

To find the volume of methanol, we can divide the mass of methanol by its density: Volume of methanol = (mass of methanol) / (density of methanol) Volume of methanol = 40 g / 0.8 g/mL = 50 mL

Similarly, the volume of water can be found by dividing the mass of water by its density: Volume of water = (mass of water) / (density of water) Volume of water = 60 g / 1 g/mL = 60 mL

The total volume of the solution is the sum of the volumes of methanol and water: Total volume of solution = Volume of methanol + Volume of water Total volume of solution = 50 mL + 60 mL = 110 mL

The volume fraction of methanol can be calculated by dividing the volume of methanol by the total volume of the solution and multiplying by 100: Volume fraction of methanol = (Volume of methanol / Total volume of solution) * 100 Volume fraction of methanol = (50 mL / 110 mL) * 100 ≈ 45.45%

Therefore, the volume fraction of methanol in the water solution is approximately 45.45%.