Question

Серная кислота массой 15,6 г прореагировала с раствором гидроксида бария. Вычисли массу образовавшейся соли. срочно с оформлением пж пж срочно

Answer 1

напишем реакцию:

H2SO4+Ba(OH)2-->BaSO4+2H2O

найдем хим.кол. H2SO4:

n(H2SO4)=15,6:98≈0,16моль

напишем реакцию и поставим химическое количество:

0,16. х

H2SO4+Ba(OH)2-->BaSO4+2H2O

х=0,16моль

найдем массу соли:

m(BaSO4)=0,16×233=37,28г

Answer 2

Calculation of the Mass of the Formed Salt

To calculate the mass of the formed salt, we need to determine the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and barium hydroxide (Ba(OH)2).

The balanced chemical equation for the reaction is as follows:

H2SO4 + Ba(OH)2 → BaSO4 + 2H2O

From the balanced equation, we can see that one mole of sulfuric acid reacts with one mole of barium hydroxide to produce one mole of barium sulfate and two moles of water.

To find the mass of the formed salt (barium sulfate), we need to know the molar mass of barium sulfate (BaSO4). The molar mass of BaSO4 can be calculated by adding up the atomic masses of its constituent elements:

- Barium (Ba): 137.33 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol (there are four oxygen atoms in BaSO4)

Adding up these atomic masses gives us the molar mass of BaSO4:

Molar mass of BaSO4 = (1 * 137.33) + (1 * 32.07) + (4 * 16.00) = 233.39 g/mol

Now, we can calculate the mass of the formed salt using the given mass of sulfuric acid (15.6 g) and the molar ratio between sulfuric acid and barium sulfate:

1 mole of H2SO4 reacts with 1 mole of BaSO4.

To calculate the number of moles of H2SO4, we divide the given mass by the molar mass of H2SO4:

Number of moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4

Number of moles of H2SO4 = 15.6 g / (2 * 1.01 + 32.07 + 4 * 16.00) g/mol

Number of moles of H2SO4 ≈ 0.156 mol

Since the molar ratio between H2SO4 and BaSO4 is 1:1, the number of moles of BaSO4 formed will also be 0.156 mol.

Finally, we can calculate the mass of the formed salt (BaSO4) using the number of moles and the molar mass of BaSO4:

Mass of BaSO4 = Number of moles of BaSO4 * Molar mass of BaSO4

Mass of BaSO4 = 0.156 mol * 233.39 g/mol

Mass of BaSO4 ≈ 36.35 g

Therefore, the mass of the formed salt (barium sulfate) is approximately 36.35 grams.