Question

СРОЧНО ДАМ 20 БАЛОВ Рассчитать массу аммиака, полученного при нагревании 50г хлорида аммония с гидроксидом натрия. Массовая доля выхода продукта 80%

Answer 1

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Answer 2

Calculation of the Mass of Ammonia Produced

To calculate the mass of ammonia produced, we need to consider the reaction between ammonium chloride (NH4Cl) and sodium hydroxide (NaOH). The balanced chemical equation for this reaction is:

NH4Cl + NaOH → NH3 + H2O + NaCl

From the equation, we can see that one mole of ammonium chloride reacts with one mole of sodium hydroxide to produce one mole of ammonia. The molar mass of ammonium chloride (NH4Cl) is approximately 53.49 g/mol, and the molar mass of ammonia (NH3) is approximately 17.03 g/mol.

Given that the mass of ammonium chloride is 50 g and the mass fraction of the product is 80%, we can calculate the mass of ammonia produced as follows:

1. Calculate the moles of ammonium chloride: - Moles of NH4Cl = Mass of NH4Cl / Molar mass of NH4Cl - Moles of NH4Cl = 50 g / 53.49 g/mol

2. Calculate the moles of ammonia produced: - Moles of NH3 = Moles of NH4Cl

3. Calculate the mass of ammonia produced: - Mass of NH3 = Moles of NH3 * Molar mass of NH3

Let's calculate the mass of ammonia produced using the given information:

1. Calculate the moles of ammonium chloride: - Moles of NH4Cl = 50 g / 53.49 g/mol = 0.935 mol

2. Calculate the moles of ammonia produced: - Moles of NH3 = 0.935 mol

3. Calculate the mass of ammonia produced: - Mass of NH3 = 0.935 mol * 17.03 g/mol = 15.94 g

Therefore, the mass of ammonia produced when 50 g of ammonium chloride reacts with sodium hydroxide, with a mass fraction of 80%, is approximately 15.94 grams.