Question

Какой V F2 при нормальных условиях реагирует с 27 г Al

Answer 1

Ответ:

33,6 л

Объяснение:

2Al + 3F₂ = 2AlF₃

m(Al)=27 г

M(Al)=27 г/моль

V=22,4 л/моль

m(Al)/(2M(Al))=V(F₂)/(3V)

V(F₂)=3Vm(Al)/(2M(Al))

V(F₂)=3*22,4*27/(2*27)=33,6 л

Answer 2

Reaction of V and Al at Normal Conditions

Under normal conditions, vanadium (V) reacts with aluminum (Al) to form vanadium(III) oxide (V2O3) and aluminum oxide (Al2O3).

The balanced chemical equation for the reaction is:

4V + 3Al → 2V2O3 + 3Al2O3

This reaction occurs at high temperatures and is used in the production of vanadium alloys and in certain industrial processes.

The reaction can be represented as follows: ``` 4V + 3Al -> 2V2O3 + 3Al2O3 ```

The reaction between vanadium and aluminum is an important process in the production of various materials and compounds.