Question

СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА К 120 г 3% раствора сульфата натрия добавили 3 г сульфата натрия. какова омега нового раствора?

Answer 1

Ответ:

64%

Объяснение:

m(р-ра)=120 г

w(Nа2SО4)=80%=0,8

+ m(Н2О)=30 г

w2(Nа2SО4)=?

Найдем массу соли Nа2SО4в первом растворе

m (Nа2SО4)= w* m(р-ра)= 0,8*120 г=96 г

Когда добавили 30 г воды масса раствора изменилась и стала

m2(р-ра)= 120+30=150г

w2= m (Nа2SО4)/ m2(р-ра)=96/150=0,64*100%=64%

Answer 2

Calculation of the Concentration of the New Solution

To calculate the concentration of the new solution, we need to consider the initial concentration of the 120 g 3% sodium sulfate solution and the additional 3 g of sodium sulfate that was added.

The initial solution is a 3% sodium sulfate solution. This means that in 100 g of the solution, there are 3 g of sodium sulfate.

When 120 g of the 3% sodium sulfate solution is taken, the amount of sodium sulfate in it can be calculated as follows:

Amount of sodium sulfate in the initial solution = (3 g/100 g) x 120 g = 3.6 g.

An additional 3 g of sodium sulfate is added to this solution. Therefore, the total amount of sodium sulfate in the new solution is:

Total amount of sodium sulfate in the new solution = 3.6 g + 3 g = 6.6 g.

To calculate the concentration of the new solution, we need to determine the total volume of the solution. Unfortunately, the volume of the initial solution is not provided in the question. Without this information, it is not possible to calculate the concentration of the new solution accurately.

Please provide the volume of the initial solution so that we can calculate the concentration of the new solution accurately.