Question

2. Який об'єм вуглекислого газу (н. у.) виділиться при повному перетворенні 90 г глюкози на спирт під час бродіння?

Answer 1

Ответ:

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Answer 2

Volume of Carbon Dioxide Produced from the Complete Conversion of 90g of Glucose to Ethanol During Fermentation

The volume of carbon dioxide produced from the complete conversion of 90g of glucose to ethanol during fermentation can be calculated using the stoichiometry of the reaction.

The balanced chemical equation for the fermentation of glucose to ethanol is: C6H12O6 → 2C2H5OH + 2CO2

From this equation, it's clear that for every mole of glucose fermented, 2 moles of ethanol and 2 moles of carbon dioxide are produced.

To calculate the volume of carbon dioxide produced, we can use the ideal gas law, which states that 1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters.

Given: - 1 mole of glucose (C6H12O6) = 180 grams - 90 grams of glucose is to be converted

Using the molar mass of glucose, we can calculate the number of moles of glucose: 90g / 180g/mol = 0.5 moles of glucose

According to the stoichiometry of the reaction, for every mole of glucose fermented, 2 moles of carbon dioxide are produced. Therefore, the number of moles of carbon dioxide produced is: 0.5 moles of glucose * 2 moles of CO2/mole of glucose = 1 mole of CO2

At STP, 1 mole of any gas occupies 22.4 liters. Therefore, the volume of carbon dioxide produced from the complete conversion of 90g of glucose to ethanol during fermentation is: 1 mole * 22.4 L/mole = 22.4 liters of CO2

So, the volume of carbon dioxide produced from the complete conversion of 90g of glucose to ethanol during fermentation is 22.4 liters. [[1]]