Question

У кімнаті 38, 1 л повітря. Скільки л чистого Кисню у кімнаті ?

Answer 1

Ответ:

V(O)=V(повиьря)×w(O)=38,1×0,209=7,9629 литров

Ответ: 7,9629 литров

Answer 2

Calculating the Amount of Oxygen in the Room

To calculate the amount of oxygen in the room, we can use the ideal gas law formula, which is expressed as:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin

Given: - Room volume (V) = 38 m³ - Pressure (P) = 1 atm - Temperature (T) = Not provided - Ideal gas constant (R) = 0.0821 L·atm/(K·mol)

We can calculate the number of moles of oxygen using the ideal gas law and then convert it to liters.

Calculation

Using the ideal gas law, we can solve for the number of moles of oxygen (n):

n = PV / RT

Assuming the temperature is 298 K (25°C), we can calculate the number of moles of oxygen.

Given: - P = 1 atm - V = 38 m³ - R = 0.0821 L·atm/(K·mol) - T = 298 K

n = (1 atm) * (38 m³) / (0.0821 L·atm/(K·mol) * 298 K)

n ≈ 1.61 moles

Now, to convert moles to liters, we can use the fact that 1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters.

Volume of oxygen = 1.61 moles * 22.4 L/mole

Volume of oxygen ≈ 36.0 liters

So, there are approximately 36.0 liters of pure oxygen in the room.