Question

Помгите пожалуйста!!! Дано: Сполука Fe2O3 Знайти масові частки ὼ(Fe)- ?ὼ(O)- ?

Answer 1

Дано:

Fe2O3

___________

ὼ(Fe)- ?

ὼ(O)- ?

Розв'язок:

ὼ=N*Ar/Mr

Mr(Fe2O3)=160

ὼ(Fe)=2*56/160=0,7=70%

ὼ(O)=3*16/160=0,3=30%

Answer 2

I can help you with your question.

The user's message is in Ukrainian and it means: "Answer in detail. Please help!!! Given: Compound Fe2O3 Find the mass fractions x(Fe)-? x(O)-?"

To find the mass fractions of iron and oxygen in Fe2O3, we need to use the following formula:

$$x(A) = \frac{n(A) \times M(A)}{M(C)}$$

where x(A) is the mass fraction of element A, n(A) is the number of moles of element A, M(A) is the molar mass of element A, and M(C) is the molar mass of the compound.

The molar mass of Fe2O3 is 159.69 g/mol, the molar mass of Fe is 55.85 g/mol, and the molar mass of O is 16.00 g/mol.

The number of moles of Fe in Fe2O3 is 2, and the number of moles of O in Fe2O3 is 3.

Using the formula, we can calculate the mass fractions of Fe and O as follows:

$$x(Fe) = \frac{2 \times 55.85}{159.69} \approx 0.6994$$

$$x(O) = \frac{3 \times 16.00}{159.69} \approx 0.3006$$

Therefore, the mass fraction of iron in Fe2O3 is about 0.6994, and the mass fraction of oxygen in Fe2O3 is about 0.3006.Ответь+подробно.++Помгите+пожалуйста!!!+Дано:+Сполука+Fe2O3+Знайти+масові+частки+ὼ(Fe)-+?ὼ(O)-+?