Question

Очисліть масу етину (С2Н2) об'ємом 2,24 за (н.у)СРОЧНОООООО​

Answer 1

Ответ:

m(C2H2) = 2,6 г

Объяснение:

Дано :

V(CH2H2) = 2,24 л

Найти :

m(CH2) - ?

1) n = V/Vm

Vm  = 22,4 л/моль

n(C2H2) = 2.24 л/22,4 л/моль = 0,1 моль

n(C2H2) = 0,1 моль

2) m = n*M

M(C2H2) = 12*2+1*2 = 26 г/моль

m(C2H2) = 0,1 моль * 26 г/моль = 2,6 г

m(C2H2) = 2,6 г

Ответ : m(C2H2) = 2,6 г

Answer 2

Calculating the Mass of Ethyne (C2H2) at Standard Temperature and Pressure (STP)

To calculate the mass of ethyne (C2H2) at standard temperature and pressure (STP), we can use the ideal gas law equation, which is expressed as:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

At STP, the conditions are: - Pressure (P) = 1 atmosphere (atm) or 101.3 kPa - Temperature (T) = 0°C or 273.15 K - Volume (V) = 22.4 liters (L) for 1 mole of gas

Calculating the Number of Moles of Ethyne

First, we need to calculate the number of moles of ethyne using the given volume of 2.24 L at STP.

The formula to calculate the number of moles is:

n = V / 22.4

Where: - n = number of moles - V = volume in liters

Substituting the given volume: n = 2.24 / 22.4 = 0.1 moles

Calculating the Mass of Ethyne

The molar mass of ethyne (C2H2) can be calculated by adding the atomic masses of the constituent atoms.

- Carbon (C) has a molar mass of approximately 12.01 g/mol. - Hydrogen (H) has a molar mass of approximately 1.008 g/mol.

The molar mass of ethyne (C2H2) is: 2 * (12.01 g/mol) + 2 * (1.008 g/mol) = 26.04 g/mol

Now, we can calculate the mass of 0.1 moles of ethyne: Mass = number of moles * molar mass = 0.1 moles * 26.04 g/mol = 2.604 g

Therefore, the mass of ethyne (C2H2) with a volume of 2.24 L at STP is approximately 2.604 grams.