Question

Какой объем кислорода потребуется для сжигания 6,8 г. аммиака? Можете расписать пожалуйста

Answer 1

Ответ:

100 грамм ..............в...о....д....к....и

Answer 2

Calculating Oxygen Volume Required to Burn 6.8g of Ammonia

To calculate the volume of oxygen required to burn 6.8g of ammonia, we can use the balanced chemical equation for the combustion of ammonia.

The balanced chemical equation for the combustion of ammonia is: 4NH3 + 5O2 → 4NO + 6H2O

According to the balanced chemical equation, 4 moles of ammonia react with 5 moles of oxygen to produce 4 moles of nitric oxide and 6 moles of water.

Calculation Steps

1. Calculate the moles of ammonia (NH3) - Given mass of ammonia = 6.8g - Molar mass of ammonia (NH3) = 17.031 g/mol - Moles of ammonia = Given mass / Molar mass - Moles of ammonia = 6.8g / 17.031 g/mol

2. Calculate the moles of oxygen (O2) - According to the balanced chemical equation, 4 moles of ammonia react with 5 moles of oxygen. - Moles of oxygen = (Moles of ammonia) * (5/4)

3. Convert moles of oxygen to volume at standard conditions - At standard conditions (0°C and 1 atm), 1 mole of any gas occupies 22.4 liters. - Volume of oxygen required = Moles of oxygen * 22.4 liters/mol

Calculation

1. Moles of ammonia: - Moles of ammonia = 6.8g / 17.031 g/mol = 0.399 moles

2. Moles of oxygen: - Moles of oxygen = 0.399 moles * (5/4) = 0.49875 moles

3. Volume of oxygen required: - Volume of oxygen = 0.49875 moles * 22.4 liters/mol = 11.18 liters

Therefore, the volume of oxygen required to burn 6.8g of ammonia is approximately 11.18 liters.