Question

У реакцію з Нітроген(V)оксидом вступила вода масою 50г Обчисліть, який об’єм Нітроген(V) оксиду (н.у) прореагував.

Answer 1

Ответ:

вот

Объяснение:

Answer 2

Reaction of Nitrogen(V) Oxide with Water

When nitrogen(V) oxide reacts with water, it forms nitric acid and nitrous acid. The balanced chemical equation for this reaction is:

2NO2(g) + H2O(l) → HNO3(aq) + HNO2(aq)

To calculate the volume of nitrogen(V) oxide that reacted, we can use the given mass of water (50g) and the molar mass of water to find the moles of water, and then use the stoichiometry of the balanced chemical equation to find the moles of nitrogen(V) oxide that reacted.

Calculations

1. Molar Mass of Water (H2O): - The molar mass of water (H2O) is 18.015 g/mol.

2. Moles of Water: - Moles = Mass / Molar Mass - Moles = 50g / 18.015 g/mol - Moles ≈ 2.775 mol

3. Moles of Nitrogen(V) Oxide: - From the balanced chemical equation, 2 moles of nitrogen(V) oxide react with 1 mole of water. - Therefore, moles of nitrogen(V) oxide = 2 * moles of water - Moles of nitrogen(V) oxide ≈ 2 * 2.775 mol - Moles of nitrogen(V) oxide ≈ 5.55 mol

Conclusion

Based on the given mass of water (50g), approximately 5.55 moles of nitrogen(V) oxide reacted in this chemical reaction.