Question

Помогите пожалуйста! Подобрать коэффициенты методом электронного баланса в О.В.Р. *** Na+ H2SO4→Na2SO4 + H2S + H2O *** Zn + HNO3→Zn(NO3)2 + NO + H2O ***CuO + NH3→ Cu + N2 +H2O ****H2S+ KMnO4+ H2SO4 →S + MnSO4 + K2SO4 + H2O ***Ca3(PO4)2 + C + SiO2→CaSiO3 + P4 + CO *** Au(NO3)2→ Au + N2 + O2

Answer 1

Держи………………………………………….

Answer 2

Balancing Chemical Equations Using the Electron Balance Method

To balance the chemical equations using the electron balance method, we need to ensure that the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction. Let's balance the given chemical equations using this method.

1. Balancing the Equation: Na + H2SO4 → Na2SO4 + H2S + H2O

First, we need to identify the oxidation states of the elements involved in the reaction. In this case, sodium (Na) is oxidized from 0 to +1, and sulfur (S) is reduced from +6 to -2.

The balanced equation using the electron balance method is: ``` 2Na + H2SO4 → Na2SO4 + 2H2S + 2H2O ```

This balances the equation by ensuring that the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction.

2. Balancing the Equation: Zn + HNO3 → Zn(NO3)2 + NO + H2O

In this equation, zinc (Zn) is oxidized from 0 to +2, and nitrogen (N) is reduced from +5 to +2.

The balanced equation using the electron balance method is: ``` Zn + 4HNO3 → Zn(NO3)2 + 2NO2 + 2H2O ```

3. Balancing the Equation: CuO + NH3 → Cu + N2 + H2O

Here, copper (Cu) is reduced from +2 to 0, and nitrogen (N) is oxidized from -3 to 0.

The balanced equation using the electron balance method is: ``` 3CuO + 2NH3 → 3Cu + N2 + 3H2O ```

4. Balancing the Equation: H2S + KMnO4 + H2SO4 → S + MnSO4 + K2SO4 + H2O

In this equation, sulfur (S) is oxidized from -2 to +6, and manganese (Mn) is reduced from +7 to +2.

The balanced equation using the electron balance method is: ``` 8H2S + 2KMnO4 + 9H2SO4 → 8S + 2MnSO4 + K2SO4 + 18H2O ```

5. Balancing the Equation: Ca3(PO4)2 + C + SiO2 → CaSiO3 + P4 + CO

Calcium (Ca) is reduced from +3 to +2, and phosphorus (P) is oxidized from -3 to 0.

The balanced equation using the electron balance method is: ``` 2Ca3(PO4)2 + 6C + 10SiO2 → 6CaSiO3 + P4 + 6CO ```

6. Balancing the Equation: Au(NO3)2 → Au + N2 + O2

Gold (Au) is reduced from +3 to 0, and nitrogen (N) is oxidized from +5 to 0.

The balanced equation using the electron balance method is: ``` 2Au(NO3)2 → 2Au + 4NO2 + O2 ```

These balanced chemical equations have been derived using the electron balance method, ensuring that the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction.