Question

1) P+O2→ P 2O2 2) P+H2→H3P 3) Ca + P→ Ca3P2 Уравнять, составить ОВР 9 класс

Answer 1

1)P(0)+O2(0)-->P2(+2)O2(-2)

2P(0)-4e-->2P(+2)

2O(0)+4e-->2O(-2)

расставим коэффициенты:

2P+O2-->P2O2

2)P(0)+H2(0)-->H3(+1)P(-3)

2P(0)+6e-->2P(-3)

6H(0)-6e-->6H(+1)

расставим коэффициенты:

2P+3H2-->2H3P

3)Ca(0)+P(0)-->Ca3(2)P2(-3)

2P(0)-6e-->P(-3)

3Ca(0)-6e-->3Ca(+2)

расставим коэффициенты:

3Ca+2P-->Ca3P2

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided, we'll go through each one step by step.

1) P + O2 → P2O5

To balance this equation, we need to ensure that there are the same number of each type of atom on both sides of the equation.

The balanced equation is: 4P + 5O2 → 2P2O5

2) P + H2 → PH3

The balanced equation is: P + 3H2 → PH3

3) Ca + P → Ca3P2

The balanced equation is: 3Ca + 2P → Ca3P2

Now, all the given chemical equations are balanced. If you have any more questions or need further assistance, feel free to ask!