Question

Скільки молекул міститься у54 грам нітратної кислоти? Дуже срочно будь ласка ​

Answer 1

m(HNO3) = 54

N(HNO3) - ?

Решение:

1) μ(HNO3) = 54 г / 63 г/моль = 0.857 моль

N(HNO3) = 0.857 моль * 6,02 ^ 23 1/моль = 5.15914 ^ 23

P.S: ^ - Знак степени

Ответ:  5.15914 ^ 23

Answer 2

Calculating the Number of Molecules in 54 Grams of Nitric Acid

To calculate the number of molecules in 54 grams of nitric acid (HNO3), we can use the following steps:

1. Calculate the Molar Mass of Nitric Acid (HNO3) - The molar mass of nitric acid (HNO3) can be calculated by adding up the atomic masses of its constituent atoms. The atomic masses are as follows: - Hydrogen (H): 1.008 g/mol - Nitrogen (N): 14.007 g/mol - Oxygen (O): 15.999 g/mol

- Using these atomic masses, the molar mass of nitric acid (HNO3) can be calculated as: ``` Molar mass of HNO3 = (1 * atomic mass of H) + (1 * atomic mass of N) + (3 * atomic mass of O) = (1 * 1.008) + (1 * 14.007) + (3 * 15.999) = 1.008 + 14.007 + 47.997 = 63.012 g/mol ```

2. Calculate the Number of Moles of Nitric Acid - The number of moles of nitric acid can be calculated using the formula: ``` Moles = Mass / Molar mass ```

- Substituting the given mass (54 grams) and the molar mass of nitric acid (63.012 g/mol) into the formula: ``` Moles = 54 g / 63.012 g/mol ≈ 0.857 moles ```

3. Calculate the Number of Molecules - The Avogadro's number, 6.022 x 10^23, represents the number of molecules in one mole of a substance.

- To find the number of molecules in 0.857 moles of nitric acid: ``` Number of molecules = Moles * Avogadro's number ≈ 0.857 moles * 6.022 x 10^23 molecules/mol ≈ 5.16 x 10^23 molecules ```

Conclusion

Therefore, approximately 5.16 x 10^23 molecules are present in 54 grams of nitric acid.