Question

Скласти рівняння реакцій взаємодії складних речовин з киснем: CH4+O2-->C6H12O6+O2-->CuS+O2-->C3H8+O2-->PH3+O2-->Срочноооо.♡Заранее спасибо♡​

Answer 1

CH4 + 2O2 => CO2 + 2H2O

C6H12O6 + 6O2 => 6CO2 + 6H2O

2CuS + 3O2 => 2CuO + 2SO2

C3H8 + 5O2 => 3CO2 + 4H2O

2PH3 + 4O2 => P2O5 + 3H2O

Answer 2

Balancing Equations for the Reactions with Oxygen:

1. CH4 + 2O2 -> CO2 + 2H2O 2. C6H12O6 + 6O2 -> 6CO2 + 6H2O 3. 2CuS + 3O2 -> 2CuO + 2SO2 4. C3H8 + 5O2 -> 3CO2 + 4H2O 5. 4PH3 + 8O2 -> P4O10 + 6H2O

Let's go through each reaction and balance the equations step by step.

1. CH4 + 2O2 -> CO2 + 2H2O: - The carbon (C) atoms are already balanced. - The hydrogen (H) atoms are balanced with 4 on each side. - The oxygen (O) atoms are not balanced. There are 4 on the left side and 4 on the right side. - To balance the oxygen atoms, we need to add a coefficient of 2 in front of the O2 on the left side. - The balanced equation is: CH4 + 2O2 -> CO2 + 2H2O.

2. C6H12O6 + 6O2 -> 6CO2 + 6H2O: - The carbon (C) atoms are not balanced. There are 6 on the left side and 6 on the right side. - To balance the carbon atoms, we need to add a coefficient of 6 in front of the CO2 on the right side. - The hydrogen (H) atoms are already balanced. - The oxygen (O) atoms are not balanced. There are 12 on the left side and 18 on the right side. - To balance the oxygen atoms, we need to add a coefficient of 6 in front of the O2 on the left side. - The balanced equation is: C6H12O6 + 6O2 -> 6CO2 + 6H2O.

3. 2CuS + 3O2 -> 2CuO + 2SO2: - The copper (Cu) atoms are not balanced. There are 2 on the left side and 2 on the right side. - To balance the copper atoms, we need to add a coefficient of 2 in front of the CuO on the right side. - The sulfur (S) atoms are already balanced. - The oxygen (O) atoms are not balanced. There are 6 on the left side and 4 on the right side. - To balance the oxygen atoms, we need to add a coefficient of 3 in front of the O2 on the left side. - The balanced equation is: 2CuS + 3O2 -> 2CuO + 2SO2.

4. C3H8 + 5O2 -> 3CO2 + 4H2O: - The carbon (C) atoms are not balanced. There are 3 on the left side and 3 on the right side. - To balance the carbon atoms, we need to add a coefficient of 3 in front of the CO2 on the right side. - The hydrogen (H) atoms are not balanced. There are 8 on the left side and 8 on the right side. - To balance the hydrogen atoms, we don't need to make any changes. - The oxygen (O) atoms are not balanced. There are 10 on the left side and 12 on the right side. - To balance the oxygen atoms, we need to add a coefficient of 5 in front of the O2 on the left side. - The balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O.

5. 4PH3 + 8O2 -> P4O10 + 6H2O: - The phosphorus (P) atoms are not balanced. There are 4 on the left side and 4 on the right side. - To balance the phosphorus atoms, we need to add a coefficient of 4 in front of the P4O10 on the right side. - The hydrogen (H) atoms are not balanced. There are 12 on the left side and 12 on the right side. - To balance the hydrogen atoms, we don't need to make any changes. - The oxygen (O) atoms are not balanced. There are 16 on the left side and 26 on the right side. - To balance the oxygen atoms, we need to add a coefficient of 8 in front of the O2 on the left side. - The balanced equation is: 4PH3 + 8O2 -> P4O10 + 6H2O.

I hope this helps! Let me know if you have any further questions.