Question

30 БАЛЛОВ Установіть, яка речовина пропущена у схемі перетворень:натрій → ... → натрій гідроксид → натрій сульфат.1)натрій гідрогенкарбонат2)натрій нітрат 3)натрій ортофосфат4)натрій оксид ​

Answer 1

Ответ: 4 .

4Na + O2 = 2Na2O

Na2O + H2O = 2NaOH

Answer 2

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Answer in detail. 30 POINTS. Determine which substance is missing in the scheme of transformations: sodium → ... → sodium hydroxide → sodium sulfate. 1) sodium hydrogen carbonate 2) sodium nitrate 3) sodium orthophosphate 4) sodium oxide

The correct answer is 4) sodium oxide. Here is the explanation:

Sodium reacts with oxygen to form sodium oxide, according to the equation:

$$4Na + O_2 \rightarrow 2Na_2O$$

Sodium oxide reacts with water to form sodium hydroxide, according to the equation:

$$Na_2O + H_2O \rightarrow 2NaOH$$

Sodium hydroxide reacts with sulfuric acid to form sodium sulfate and water, according to the equation:

$$2NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O$$

Therefore, the missing substance in the scheme of transformations is sodium oxide.

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