Question

на натрій сульфід кількістю речовини 0.3 моль подіяли хлоридною кислотою. обчисліть обєм газу що виділився. назвіть утворену сіль​

Answer 1

Ответ:

6,72 л

Объяснение:

Na₂S + 2HCl = 2NaCl + H₂S↑

                   хлорид натрия

n(Na₂S)=0,3 моль

V=22,4 л/моль

по схеме реакции:

V(H₂S)/V = n(Na₂S)

V(H₂S)=Vn(Na₂S)

V(H₂S)=22,4*0,3=6,72 л

Answer 2

Reaction of Sodium Sulfide with Hydrochloric Acid

When 0.3 moles of sodium sulfide (Na2S) react with hydrochloric acid (HCl), the following chemical reaction occurs:

Chemical Equation: 2Na2S + 2HCl -> 2NaCl + H2S

This reaction produces sodium chloride (NaCl) and hydrogen sulfide (H2S) gas.

Calculation of Gas Volume Produced

To calculate the volume of gas produced, we can use the ideal gas law equation:

Ideal Gas Law Equation: PV = nRT

Where: - P = pressure of the gas - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin

Given: - n = 0.3 moles - R = 0.0821 L·atm/(K·mol) (ideal gas constant at standard conditions) - T = standard temperature (usually 273.15 K or 0°C)

We can assume standard temperature and pressure (STP) conditions, where the temperature is 0°C or 273.15 K, and the pressure is 1 atm.

Using the ideal gas law equation, we can solve for V (volume of the gas).

Calculation: PV = nRT V = (nRT)/P V = (0.3 moles * 0.0821 L·atm/(K·mol) * 273.15 K) / 1 atm V ≈ 6.73 liters

So, the volume of gas produced is approximately 6.73 liters.

Name of the Salt Formed

The salt formed in this reaction is sodium chloride (NaCl), which is a white crystalline solid and is commonly known as table salt.

Therefore, the salt formed in the reaction is sodium chloride (NaCl).