Question

Розрахувати масу та кількість речовини солі, яка утворилась під час взаємодії ферум(ІІ) оксиду масою 320 г. з хлоридною кислотою.​

Answer 1

FeO + 2HCl = FeCl2 + H2O

m(FeO) = 320 г

m(FeCl2) - ?

μ(FeCl2) - ?

Решение:

1) μ(FeCl2) = μ(FeO) = 320 г / 72 г/моль = 4,45 моль

2) m(FeCl2) = 4,45 моль * 127 г/моль = 565,15 г

Ответ: 565,15 г

Answer 2

Calculation of Mass and Amount of Salt Formed

To calculate the mass and amount of salt formed during the reaction between iron(II) oxide and hydrochloric acid, we need to determine the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between iron(II) oxide (FeO) and hydrochloric acid (HCl) is as follows:

FeO + 2HCl -> FeCl2 + H2O

According to the equation, 1 mole of FeO reacts with 2 moles of HCl to produce 1 mole of FeCl2 and 1 mole of H2O.

Given that the mass of iron(II) oxide (FeO) is 320 g, we need to convert this mass into moles using the molar mass of FeO.

The molar mass of FeO can be calculated by adding the atomic masses of iron (Fe) and oxygen (O):

Fe: 55.845 g/mol O: 16.00 g/mol

Molar mass of FeO = 55.845 g/mol + 16.00 g/mol = 71.845 g/mol

To calculate the number of moles of FeO, we divide the given mass by the molar mass:

Number of moles of FeO = 320 g / 71.845 g/mol = 4.45 mol (rounded to two decimal places)

Since the balanced chemical equation shows that 1 mole of FeO reacts with 1 mole of FeCl2, the number of moles of FeCl2 formed will also be 4.45 mol.

Now, to calculate the mass of FeCl2 formed, we need to multiply the number of moles by the molar mass of FeCl2.

The molar mass of FeCl2 can be calculated by adding the atomic masses of iron (Fe) and chlorine (Cl):

Fe: 55.845 g/mol Cl: 35.453 g/mol

Molar mass of FeCl2 = 55.845 g/mol + 2 * 35.453 g/mol = 126.743 g/mol

Mass of FeCl2 formed = 4.45 mol * 126.743 g/mol = 563.39 g (rounded to two decimal places)

Therefore, the mass of salt (FeCl2) formed during the reaction is approximately 563.39 grams.

Please note that this calculation assumes that the reaction goes to completion and that there are no other side reactions or losses during the process.