Question

CuSO4—Cu(OH)2—CuCl2—Cu(OH)2—CuO

Answer 1

CuSO4+2NaOH=Cu(OH)2+Na2SO4

Cu(OH)2+2NaCl=2NaOH+CuCl2

CuCl2+2NaOH=2NaCl+Cu(OH)2

Cu(OH)2=CuO+H2O

Answer 2

The series of chemical reactions you have provided involves the transformation of copper sulfate (CuSO4) into copper(II) oxide (CuO) via several intermediate steps. Let's go through each reaction:

1. CuSO4: Copper sulfate is a compound composed of copper (Cu), sulfur (S), and oxygen (O). It is usually found as a blue crystalline solid when hydrated. The formula for the hydrated form is CuSO4·5H2O.

2. CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4: When copper sulfate reacts with sodium hydroxide (NaOH), a double displacement reaction occurs. Copper sulfate reacts with sodium hydroxide to form copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4) as a byproduct.

3. Cu(OH)2 + 2HCl → CuCl2 + 2H2O: Copper(II) hydroxide reacts with hydrochloric acid (HCl) to produce copper(II) chloride (CuCl2) and water (H2O). This is another double displacement reaction where the hydroxide ions from the copper hydroxide react with the hydrogen ions from the hydrochloric acid.

4. CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl: Copper(II) chloride reacts with sodium hydroxide in a double displacement reaction, producing copper(II) hydroxide and sodium chloride (NaCl) as the other product.

5. 2Cu(OH)2 → CuO + H2O: Copper(II) hydroxide decomposes upon heating, resulting in the formation of copper(II) oxide and water. This is a thermal decomposition reaction.

In summary, the series of reactions you provided can be described as the conversion of copper sulfate into copper(II) oxide through the formation of copper hydroxide, its conversion to copper(II) chloride, and subsequent reformation of copper hydroxide before finally decomposing into copper(II) oxide and water upon heating.