Question

CH4->C2H2->C2H4O->C2H4O2->CH3COONa​

Answer 1

Ответ:

Объяснение:

2CH4 -> CH=-CH + 3H2 (1500C)

CH=-CH + H2O -> CH3COH (t, Hg)

CH3COH + Ag2O -> CH3COOH + 2Ag (NH3)

CH3COOH + NaOH -> CH3COONa + H2O

Answer 2

The given sequence represents a series of chemical reactions. Here's a breakdown of each reaction:

1. CH4 (methane) -> C2H2 (acetylene): This reaction involves the removal of two hydrogen atoms from methane (CH4) to form acetylene (C2H2).

2. C2H2 (acetylene) -> C2H4O (ethenone or ketene): This reaction involves the addition of an oxygen atom to acetylene (C2H2), resulting in the formation of ethenone (C2H4O), also known as ketene.

3. C2H4O (ethenone or ketene) -> C2H4O2 (acetic acid or ethanoic acid): This reaction involves the oxidation of ethenone (C2H4O) to form acetic acid (C2H4O2) or ethanoic acid.

4. C2H4O2 (acetic acid or ethanoic acid) -> CH3COONa (sodium acetate): This reaction involves the neutralization of acetic acid (C2H4O2) with sodium hydroxide (NaOH), resulting in the formation of sodium acetate (CH3COONa).

In summary, the given sequence represents a transformation from methane (CH4) to acetylene (C2H2), then to ethenone (C2H4O), further to acetic acid (C2H4O2), and finally to sodium acetate (CH3COONa). Each step involves specific chemical reactions that lead to the formation of the subsequent compound.