Question

C3H8->C3H6->C3H6Br2->C3H4->C3H5Cl

Answer 1

Ответ:

1) C3H8 =(t,p,Pt) C3H6 + H2

2) C3H6 + Br2 =(свет) C3H6Br2

3) C3H6 Br2 + 2 KOH =(C2H5OH) C3H4 + 2KBr + 2H2O

4) C3H4 + HBr = C3H5Br

в скобках указаны условия проведения реакции

Answer 2

The reaction sequence you provided involves the transformation of propane (C3H8) through several steps. Let's go through each reaction step:

1. C3H8 (propane) → C3H6 (propene): In the presence of a suitable catalyst, propane can undergo dehydrogenation to form propene. This reaction removes two hydrogen atoms from propane, resulting in the formation of propene.

2. C3H6 (propene) → C3H6Br2 (1,2-dibromopropane): Propene can react with bromine (Br2) to form 1,2-dibromopropane. This reaction is an addition reaction, where the bromine atoms add to the double bond of propene.

3. C3H6Br2 (1,2-dibromopropane) → C3H4 (allene): 1,2-dibromopropane can undergo an elimination reaction to form allene (C3H4). The elimination of two bromine atoms results in the formation of a triple bond between two carbon atoms.

4. C3H4 (allene) → C3H5Cl (allyl chloride): Allene can react with hydrogen chloride (HCl) to form allyl chloride. In this reaction, the triple bond in allene is broken, and a hydrogen atom from HCl replaces one of the carbon atoms, resulting in the formation of allyl chloride.

So, the overall reaction sequence is:

C3H8 (propane) → C3H6 (propene) → C3H6Br2 (1,2-dibromopropane) → C3H4 (allene) → C3H5Cl (allyl chloride).

Please note that these reactions may require specific reaction conditions, such as appropriate catalysts or temperature ranges, and should be carried out with proper safety precautions in a controlled laboratory environment.