Question

C6H5COH+K2Cr2O7+H2SO4==

Answer 1

3C6H5-CHO + K2Cr2O7 + 4H2SO4 --  3C6H5-COOH + K2SO4 + Cr2(SO4)3 + 4H2O
C⁺¹ -2e = C⁺³              2   3 - окисление
2Cr⁺⁶ -3e*2 = 2Cr⁺³     6   1 - восстановление
C6H5-CHO  восстановитель (С⁺¹)
K2Cr2O7 окислитель (Cr⁺⁶)

Answer 2

The chemical equation you provided is not balanced. However, based on the reactants you mentioned, it appears that you're trying to write the reaction between benzaldehyde (C6H5COH), potassium dichromate (K2Cr2O7), and sulfuric acid (H2SO4). The balanced equation for this reaction is as follows:

2C6H5COH + K2Cr2O7 + 8H2SO4 → 2C6H5COOH + Cr2(SO4)3 + K2SO4 + 8H2O

In this reaction, benzaldehyde (C6H5COH) reacts with potassium dichromate (K2Cr2O7) and sulfuric acid (H2SO4) to form benzoic acid (C6H5COOH), chromium(III) sulfate (Cr2(SO4)3), potassium sulfate (K2SO4), and water (H2O). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.