Question

V(H2)=4л V(CL2)=6л Найдите: V(HCL)=?

Answer 1

v(H2)=V/Vm=6л/22,4л/моль=0,18 моль. уравнение

реакции:Cl2+H2===>2HCl

v(Cl2)=V/Vm=6л/22,4л/моль=0,27 моль

v(H2)=0,18 моль,значит v(HCl)=2*0,18моль=0,36 моль

V(HCl)=v*Vm=0,36моль*22,4л/моль=8,064 л

Ответ:V(HCl)=8,064 л

Answer 2

To determine the volume of HCl, we need to use the balanced chemical equation for the reaction between hydrogen gas (H2) and chlorine gas (Cl2) to form hydrogen chloride gas (HCl):

H2 + Cl2 → 2HCl

The balanced equation shows that 1 mole of H2 reacts with 1 mole of Cl2 to form 2 moles of HCl. Therefore, we need to determine the number of moles of each gas and use the stoichiometry of the balanced equation to determine the number of moles of HCl produced.

Assuming all gases are at the same temperature and pressure, the ideal gas law can be used to relate the volume of each gas to its number of moles:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

We can rearrange this equation to solve for the number of moles:

n = PV/RT

Using this equation, we can calculate the number of moles of each gas:

n(H2) = (1 atm)(4 L)/(0.0821 L·atm/mol·K)(273 K) = 0.162 mol n(Cl2) = (1 atm)(6 L)/(0.0821 L·atm/mol·K)(273 K) = 0.243 mol

According to the balanced equation, the reaction produces twice as many moles of HCl as the number of moles of either reactant. Therefore, the number of moles of HCl produced is:

n(HCl) = 2 × min(n(H2), n(Cl2)) = 2 × 0.162 mol = 0.324 mol

Finally, we can use the ideal gas law to calculate the volume of HCl produced:

V(HCl) = n(HCl)RT/P = (0.324 mol)(0.0821 L·atm/mol·K)(273 K)/(1 atm) = 7.18 L

Therefore, the volume of HCl produced is 7.18 L.