Question

Na2SO3+...+koh=k2mno4+...+h20

Answer 1

Na2SO3+KOH+KMnO4=Na2SO4+ H2O +K2MnO4

Answer 2

The chemical equation you provided is not balanced and is missing some reactants and products. However, I can guide you on how to balance the equation.

First, let's write the complete and balanced equation:

2 Na2SO3 + 2 KMnO4 + 2 KOH → 2 Na2SO4 + 2 MnO2 + 3 O2 + 2 H2O

Now, let's balance the equation step by step:

1. Balance the number of sodium atoms on both sides by multiplying Na2SO3 by 2:

2 Na2SO3 + 2 KMnO4 + 2 KOH → 2 Na2SO4 + 2 MnO2 + 3 O2 + 2 H2O

2. Balance the number of potassium atoms on both sides by multiplying KOH by 2:

2 Na2SO3 + 2 KMnO4 + 4 KOH → 2 Na2SO4 + 2 MnO2 + 3 O2 + 2 H2O

3. Balance the number of manganese atoms on both sides by multiplying KMnO4 by 2:

2 Na2SO3 + 4 KMnO4 + 4 KOH → 2 Na2SO4 + 2 MnO2 + 3 O2 + 2 H2O

4. Balance the number of sulfur atoms on both sides by multiplying Na2SO4 by 2:

2 Na2SO3 + 4 KMnO4 + 4 KOH → 4 Na2SO4 + 2 MnO2 + 3 O2 + 2 H2O

5. Finally, balance the number of oxygen atoms on both sides by adding O2:

2 Na2SO3 + 4 KMnO4 + 4 KOH → 4 Na2SO4 + 2 MnO2 + 6 O2 + 2 H2O

Therefore, the balanced chemical equation for the reaction is:

2 Na2SO3 + 4 KMnO4 + 4 KOH → 4 Na2SO4 + 2 MnO2 + 6 O2 + 2 H2O