Question

KOH-Zn(OH)2-K2ZnO2-ZnSO4

Answer 1

Ответ:

Объяснение:

2KOH + ZnCl2 = Zn(OH)2 + 2KCl

Zn(OH)2 + 2KOH =K2ZnO2 + 2H2O

K2ZnO2 + 2H2SO4 = K2SO4 + ZnSO4 + 2H2O

Answer 2

The sequence of compounds you provided represents a series of chemical reactions involving potassium hydroxide (KOH), zinc hydroxide (Zn(OH)2), potassium zincate (K2ZnO2), and zinc sulfate (ZnSO4). Let's break down the reactions step by step:

1. KOH + Zn(OH)2: When potassium hydroxide (KOH) reacts with zinc hydroxide (Zn(OH)2), a double displacement reaction occurs, resulting in the formation of potassium zincate (K2ZnO2) and water (H2O):

2KOH + Zn(OH)2 -> K2ZnO2 + 2H2O

2. K2ZnO2 + ZnSO4: Next, potassium zincate (K2ZnO2) reacts with zinc sulfate (ZnSO4) in a single displacement reaction, leading to the formation of potassium sulfate (K2SO4) and zinc oxide (ZnO):

K2ZnO2 + ZnSO4 -> ZnO + K2SO4

In summary, the overall reaction involving the given compounds is:

2KOH + Zn(OH)2 + ZnSO4 -> K2ZnO2 + ZnO + 2H2O + K2SO4