Question

CuSO4+BaCI2=? CuSO4+Hg=? CuSO4+Zn=? CuSO4+NaOH=? 

Answer 1

CuSO4+BaCI2=BaSO4+CuCl2

CuSO4+Hg=Cu+HgSO4

CuSO4+Zn=Cu+ZnSO4

CuSO4+2NaOH=CuOH2+Na2SO4

Answer 2

CuSO4+BaCI2=CuCl2+BaSO4

CuSO4+Hg=Cu+HgSO4

CuSO4+Zn=ZnSO4+Cu

CuSO4+2NaOH=Cu(OH)2+Na2SO4 

Answer 3

Let's calculate the products of the given chemical reactions:

1. CuSO4 + BaCl2: When CuSO4 (copper sulfate) reacts with BaCl2 (barium chloride), a double displacement reaction occurs. The positive ions switch places, resulting in the formation of new compounds. The reaction can be represented as follows:

CuSO4 + BaCl2 → CuCl2 + BaSO4

The products formed are CuCl2 (copper(II) chloride) and BaSO4 (barium sulfate).

2. CuSO4 + Hg: When CuSO4 reacts with Hg (mercury), a single displacement reaction takes place. Copper, being higher in the reactivity series than mercury, displaces mercury from its compound. The reaction can be represented as follows:

CuSO4 + Hg → Cu + HgSO4

The products formed are Cu (copper) and HgSO4 (mercury(II) sulfate).

3. CuSO4 + Zn: When CuSO4 reacts with Zn (zinc), a single displacement reaction occurs. Zinc, being higher in the reactivity series than copper, displaces copper from its compound. The reaction can be represented as follows:

CuSO4 + Zn → ZnSO4 + Cu

The products formed are ZnSO4 (zinc sulfate) and Cu (copper).

4. CuSO4 + NaOH: When CuSO4 reacts with NaOH (sodium hydroxide), a double displacement reaction occurs. The positive ions switch places, resulting in the formation of new compounds. The reaction can be represented as follows:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

The products formed are Cu(OH)2 (copper(II) hydroxide) and Na2SO4 (sodium sulfate).

Please note that these reactions are based on general chemical principles and may not account for specific conditions or concentrations.