Question

Al->Al2O3->AlCl3->Al(OH)3->KAlO2​

Answer 1

4Al + 3O2 = 2Al2O3

Al2O3 + 6HCl = 2AlCl3 + 3H2O

AlCl3 + 3NaOH = 3NaCl + Al(OH)3

2Al(OH)3 + K2O (t)= 2KAlO2 + 3H2O

Answer 2

4Al + 3O2 = 2Al2O3

Al2O3 + 6HCl = 2AlCl3 + 3H2O

AlCl3 + 3NaOH = Al(OH)3 + 3NaCl

2Al(OH)3 + K2O =(t°) 2KAlO2 +3H2O

Answer 3

The series of reactions you've mentioned involves the transformation of aluminum (Al) through several chemical compounds. Let's go through each step:

1. Al → Al2O3: This reaction represents the oxidation of aluminum metal to form aluminum oxide (Al2O3) through a process known as combustion. The balanced equation for this reaction is: 4 Al + 3 O2 → 2 Al2O3

2. Al2O3 → AlCl3: The next step involves the reaction of aluminum oxide (Al2O3) with chlorine gas (Cl2) to produce aluminum chloride (AlCl3). The balanced equation for this reaction is: 2 Al2O3 + 6 Cl2 → 4 AlCl3 + 3 O2

3. AlCl3 → Al(OH)3: In this step, aluminum chloride (AlCl3) reacts with water (H2O) to form aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl). The balanced equation for this reaction is: AlCl3 + 3 H2O → Al(OH)3 + 3 HCl

4. Al(OH)3 → KAlO2: Lastly, aluminum hydroxide (Al(OH)3) reacts with potassium hydroxide (KOH) to produce potassium aluminate (KAlO2) and water (H2O). The balanced equation for this reaction is: Al(OH)3 + KOH → KAlO2 + 3 H2O

Overall, the sequence of reactions is as follows: Al → Al2O3 → AlCl3 → Al(OH)3 → KAlO2