Question

M(HCl)=100 г w(HCl)=15% m(AgCl)-?

Answer 1

MHCl=100*0.15=15g
15g                 xg
HCl+AgNO3=AgCl|+HNO3
36.5g             142.5g

x=15*142.5/36.5=58.5g

Answer 2

To calculate the mass of AgCl formed, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between HCl and AgCl:

2AgCl + 2HCl -> 2AgCl + H2

From the equation, we can see that 2 moles of AgCl are produced for every 2 moles of HCl consumed. Therefore, the molar ratio between AgCl and HCl is 1:1.

Given that the mass of HCl (M(HCl)) is 100 grams and the weight percent of HCl (w(HCl)) is 15%, we can calculate the amount of HCl in grams:

Mass of HCl = M(HCl) * (w(HCl) / 100) = 100 g * (15 / 100) = 15 g

Since the molar ratio between AgCl and HCl is 1:1, the mass of AgCl formed will be equal to the mass of HCl consumed, which is 15 grams. Therefore, the mass of AgCl (m(AgCl)) is 15 grams.