Question

V=1 л,w=3,5% m(H2O)=?

Answer 1

18 г=22,4

Х =1

Х=0,80гр=3,5%

Х =100%

Х=280

Answer 2

To calculate the mass of water (m(H2O)) using the given information, we need to know the volume (V) and the weight percent (w%) of water in the solution.

The weight percent (w%) represents the mass of water divided by the total mass of the solution, multiplied by 100. In this case, the weight percent is 3.5%.

To find the mass of water, we can set up the following equation:

w% = (m(H2O) / (m(H2O) + m(solution))) * 100

where m(solution) represents the mass of the solution.

Since we have the volume (V) and we assume the density of the solution is the same as water, we can calculate the mass of the solution using the density formula:

density = mass / volume

The density of water is approximately 1 g/mL or 1 kg/L.

Let's calculate the mass of the solution:

mass(solution) = density(solution) * volume(solution)

Using V = 1 L and assuming the density of the solution is 1 g/mL or 1 kg/L, we have:

mass(solution) = 1 kg/L * 1 L = 1 kg

Now we can rearrange the initial equation to solve for m(H2O):

w% = (m(H2O) / (m(H2O) + 1 kg)) * 100

3.5 = (m(H2O) / (m(H2O) + 1)) * 100

Multiplying both sides by (m(H2O) + 1):

3.5 * (m(H2O) + 1) = m(H2O)

Expanding the equation:

3.5 * m(H2O) + 3.5 = m(H2O)

Subtracting 3.5 * m(H2O) from both sides:

3.5 = -2.5 * m(H2O)

Dividing both sides by -2.5:

m(H2O) = 3.5 / -2.5

m(H2O) = -1.4 g

It seems that there is an error in the calculations, as the mass of water cannot be negative. Please check the given values and ensure they are accurate.