Question

Fe2O3 -> Fe3O4 -> FeO -> Fe -> FeCl2

Answer 1

1) FeO + H2SO4 = H2O + FeSO4 
2) FeSO4 + 2NaOH = Na2SO4 + Fe(OH)2
3) Fe(OH)2 (t) = H2O + FeO 
4) FeO + CO(t) = Fe + CO2 
5) Fe + 2HCl = H2 + FeCl2

Answer 2

The chemical reactions you've listed involve the reduction of iron(III) oxide (Fe2O3) to iron(II) chloride (FeCl2) through several intermediate steps. Let's break down each step:

1. Fe2O3: This is iron(III) oxide, also known as hematite. It consists of two iron (Fe) atoms and three oxygen (O) atoms.

2. Fe3O4: In the first step, iron(III) oxide (Fe2O3) is reduced to iron(II,III) oxide (Fe3O4), which is a mixed-valence compound. It contains both iron(II) ions (Fe2+) and iron(III) ions (Fe3+). This reaction can occur by heating Fe2O3 in the presence of carbon monoxide (CO) or hydrogen (H2).

3. FeO: The second step involves the reduction of Fe3O4 to iron(II) oxide (FeO). This reduction can be achieved by further heating Fe3O4 with carbon monoxide (CO) or hydrogen (H2).

4. Fe: In the next step, FeO is reduced to metallic iron (Fe) by removing the oxygen. This process is commonly referred to as the reduction of iron oxide.

5. FeCl2: Finally, iron metal (Fe) can react with hydrochloric acid (HCl) to form iron(II) chloride (FeCl2). The reaction involves the displacement of hydrogen from HCl by iron.

Overall, the series of reactions you've described represents the reduction of iron(III) oxide (Fe2O3) to iron(II) chloride (FeCl2) through the formation of iron(II,III) oxide (Fe3O4) and iron(II) oxide (FeO), followed by the reduction of FeO to metallic iron (Fe) and its subsequent reaction with hydrochloric acid to produce iron(II) chloride.