Question

M(H2)=3г m(O2)=64г m(H2O)=?

Answer 1

Ответ:

дано

m(H2)=3г

m(O2)=64г

-----------------

m(H2O)=?

2H2+O2-->2H2O

M(H2) = 2 g/mol

n(H2) = m/M = 3 / 2 = 1.5 mol

M(O2) = 32 g/mol

n(O2) = m/M = 64 / 32 = 2 mol

n(H2) < n(O2)

2n(H2) = 2n(H2O) = 1.5 mol

n(H2O) = 1.5 mol

M(H2O) = 18 g/mol

m(H2O) = n*M = 1.5 * 18 = 27 g

ответ 27 г

Объяснение:

Answer 2

Ответ:27 г

2H2+O2 = 2H2O

4----32-----36

3----64--x=27

Считаем по меньшему!!!(т.е. по водороду)

Answer 3

To find the mass of water (H2O) produced from the reaction between hydrogen (H2) and oxygen (O2), we need to consider the balanced chemical equation for the reaction:

2H2 + O2 → 2H2O

From the equation, we can see that 2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.

Given the mass of H2 as 3 grams, we can calculate the number of moles of H2 using its molar mass. The molar mass of hydrogen (H) is approximately 1 gram per mole. Therefore, the number of moles of H2 is:

moles of H2 = mass of H2 / molar mass of H2 = 3 g / 1 g/mol = 3 mol

Similarly, for the mass of O2 as 64 grams, we calculate the number of moles of O2. The molar mass of oxygen (O) is approximately 16 grams per mole. Therefore, the number of moles of O2 is:

moles of O2 = mass of O2 / molar mass of O2 = 64 g / 16 g/mol = 4 mol

Since the stoichiometric ratio between H2 and H2O is 2:2, the number of moles of H2O produced is the same as the number of moles of H2.

moles of H2O = moles of H2 = 3 mol

Finally, we can calculate the mass of H2O using the number of moles of H2O and its molar mass. The molar mass of water (H2O) is approximately 18 grams per mole.

mass of H2O = moles of H2O * molar mass of H2O = 3 mol * 18 g/mol = 54 g

Therefore, the mass of water (H2O) produced from the given reaction is 54 grams.