Question

Галактика отдаляется от Земли со скоростью 220,7331 км/с . На каком расстоянии от Земли расположена эта Галактика. Ответ предоставить в св.годах.

Answer 1

Ответ:

Объяснение:

Закон Хаббла -это  линейное соотношение между скоростью, с которой удаляются галактики, и расстоянием до них.

V = r * H где r -  расстояние до  галактики,  H - постоянная Хаббла,  принимаем ее 67 (км/с)/Мпк. Отсюда имеем:

r = V/H = 220,7331/67 ≈ 3,29452 Мпк.≈ 10745287,09 световых лет

1 Мпк = 3,262 * 10^6 световых лет

Answer 2

Distance of the Galaxy from Earth

The galaxy is moving away from Earth at a speed of 220,7331 km/s. To determine the distance of the galaxy from Earth, we need to consider the concept of redshift. Redshift is a phenomenon in which light from distant objects, such as galaxies, appears to be shifted towards longer wavelengths. This shift is caused by the expansion of the universe.

The relationship between the redshift of an object and its distance from Earth is described by Hubble's law. According to Hubble's law, the recessional velocity of a galaxy is directly proportional to its distance from Earth. The equation for Hubble's law is:

v = H0 * d

Where: - v is the recessional velocity of the galaxy, - H0 is the Hubble constant (which represents the rate of expansion of the universe), and - d is the distance of the galaxy from Earth.

To calculate the distance of the galaxy from Earth, we can rearrange the equation as follows:

d = v / H0

Given that the recessional velocity of the galaxy is 220,7331 km/s, we need to know the value of the Hubble constant to calculate the distance. However, the value of the Hubble constant is subject to ongoing research and refinement, and different studies may provide slightly different values.

Therefore, without the specific value of the Hubble constant, it is not possible to provide an accurate distance in light-years for the galaxy in question. To obtain the distance in light-years, we would need the value of the Hubble constant and perform the necessary calculations using the equation mentioned above.

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