Question

Cos-cos-cos3x +1 =0​

Answer 1

Ответ:

= 0

Объяснение:

1 + SIN x ≠ 0

2 cos 2x · cos x = 0       Cos x + Cos y = 2 Cos (x+y)/2 · Cos ( x - y ) /2

SIN x ≠ - 1

cos 2x = 0 /cos x = 0

x ≠ - π / 2 + 2πn

2x = π/2 + πk  или    x = π / 2 + πm

x ≠ - π/2 + 2πn

x = π/4 + πk/2  или    x = π / 2 + πm

x ≠ - π/2 + 2πn

x = π/4 + πk/2  или    x = π / 2 + 2πm

Answer 2

To solve the equation cos(cos(cos(3x))) + 1 = 0, we can use a step-by-step approach. Here's how you can solve it:

1. Start by subtracting 1 from both sides of the equation to isolate the cosine term: cos(cos(cos(3x))) = -1

2. Since the range of the cosine function is -1 to 1, it implies that the cosine of an angle can only be equal to -1 when the angle itself is an odd multiple of π. Therefore, we have: cos(cos(3x)) = π

3. Now, we need to find the values of cos(3x) that satisfy the equation cos(cos(3x)) = π. However, this equation has no real solutions because the range of the inner cosine function is -1 to 1, and π is outside that range. Therefore, there are no real solutions to the equation cos(cos(cos(3x))) + 1 = 0.

If you were looking for solutions within a specific range or if there were any additional constraints or typos in the equation, please let me know so I can assist you further.