Question

(а/а+1+1)×1+а/2а-1=​

Answer 1

Ответ:

0.5(4+а²) або ½×(4+а²)

Answer 2

It seems like you've provided a mathematical expression:

$\frac{a}{{a+1+1}} \times 1 + \frac{a}{{2a-1}}$.

Let's simplify this expression step by step:

1. The denominator $a+1+1$ simplifies to $a+2$.
2. Similarly, the denominator $2a-1$ remains as it is.

So, the expression becomes:

$\frac{a}{{a+2}} \times 1 + \frac{a}{{2a-1}}$.

Now, let's find a common denominator for both fractions, which is $(a+2)(2a-1)$:

$\frac{a \cdot (2a-1)}{{(a+2)(2a-1)}} + \frac{a \cdot (a+2)}{{(a+2)(2a-1)}}$.

Now, we can add the two fractions:

$\frac{a \cdot (2a-1) + a \cdot (a+2)}{{(a+2)(2a-1)}}$.

Distribute the 'a' terms:

$\frac{2a^2 - a + a^2 + 2a}{{(a+2)(2a-1)}}$.

Combine like terms:

$\frac{3a^2 + a}{{(a+2)(2a-1)}}$.

Factor out 'a' from the numerator:

$\frac{a(3a + 1)}{{(a+2)(2a-1)}}$.

So, the simplified expression is:

$\frac{a(3a + 1)}{{(a+2)(2a-1)}}$.