Question

Составить программу в Pascal для вычисления функции : 1) y=sin(x^2+1) 2) y= квадратный корень из x^3+2x 3) y=(x+8)/(x^3-4)

Answer 1

Begin
  var x: real;  read(x);  writeln('y(',x,') = sin(',x,'^2+1) = ',sin(sqr(x)+1));  writeln('y(',x,') = sqrt(',x,'^3+2x) = ',sqrt(power(x,3)+2*x));  writeln('y(',x,') = (x+8)/(x^3-4) = ',(x+8)/(power(x,3)-4));
end.

Answer 2

Program in Pascal for Computing Functions

Here's a Pascal program to compute the given functions:

1. Function 1: - Function: \( y = \sin(x^2 + 1) \) - Pascal code: ``` function Function1(x: real): real; begin Function1 := sin(sqr(x) + 1); end; ```

2. Function 2: - Function: \( y = \sqrt{x^3 + 2x + 3} \) - Pascal code: ``` function Function2(x: real): real; begin Function2 := sqrt(x * x * x + 2 * x + 3); end; ```

3. Function 3: - Function: \( y = \frac{x + 8}{x^3 - 4} \) - Pascal code: ``` function Function3(x: real): real; begin Function3 := (x + 8) / (x * x * x - 4); end; ```

You can use these functions in your Pascal program to compute the respective values based on the input.

Let me know if you need further assistance!