Question

Напишите программу которая в диапазоне целых двухзначных чисел от c до b определяет количество нечетных чисел кратных 3 и не начинающихся на 2 и 4

Answer 1

Var a,b,c,d:integer;
begin
b:=0;
writeln('Введите c');
readln(c);
writeln('Введите d');
readln(d);
for a:=c to d do
begin
if (a mod 2=1)and(a mod 3=0)and(a div 10<>2)and(a div 10<>4) then b:=b+1;
end;
writeln('Количество чисел равняется ',b);
end.

Answer 2

Program to Count Odd Numbers Divisible by 3

Here's a program in Python that determines the number of odd numbers divisible by 3 within the range of two-digit integers from c to b, excluding those that start with 2 or 4.

def count_odd_divisible_by_3(c, b):
    count = 0
    for num in range(c, b+1):
        if num % 2 != 0 and num % 3 == 0 and str(num)[0] not in ['2', '4']:
            count += 1
    return count

# Example usage
c = 10  # Replace with the desired value
b = 99  # Replace with the desired value
result = count_odd_divisible_by_3(c, b)
print("The number of odd numbers divisible by 3 and not starting with 2 or 4 is:", result)

You can replace the values of `c` and `b` with the desired range of two-digit integers to get the count of odd numbers divisible by 3 and not starting with 2 or 4 within that range.

Let me know if you need further assistance with this program!