Question

A2+B2->C10A2->A8->A10B2->B16->B10 A1-=218 B10=169 ПОМОГИТЕ!!!!!

Answer 1

так как A10 = 218 то и A8=A2=218

так как B10 = 169 то и B16=B2=169

тогда C10 = A2 + B2 = 218 + 169 = 387

 

Answer 2

Решение во вложении. В розовых ячейках заданы начальные значения (218 и 169). В жёлтых - формулы. В ячейке С10 получаем результат.

Answer 3

Mathematical Equation Resolution

It looks like you've provided a mathematical equation for which you need assistance. Let's break it down step by step.

Given: - A2 + B2 -> C10 - A2 -> A8 -> A10 - B2 -> B16 -> B10 - A1 = 218 - B10 = 169

Step 1: Solving for A2 and B2

We can use the given information to solve for A2 and B2.

From the equation A2 -> A8 -> A10, we can deduce that A2 = A10 - (A10 - A8).

Similarly, from the equation B2 -> B16 -> B10, we can deduce that B2 = B10 - (B10 - B16).

Substituting the given values: - A10 = A8 + (A10 - A8) - A10 = A8 + 2 - B10 = B16 + (B10 - B16) - B10 = B16 + 6

Step 2: Solving for A8 and B16

We can use the derived equations to solve for A8 and B16.

Substituting the given values: - A10 = A8 + 2 - A8 = A10 - 2 - A8 = A2 - B10 = B16 + 6 - B16 = B10 - 6 - B16 = B2

Step 3: Solving for C10

Now that we have A2 and B2, we can use the equation A2 + B2 -> C10 to solve for C10.

Substituting the given values: - A2 = 218 - B2 = 169 - C10 = A2 + B2 - C10 = 218 + 169 - C10 = 387

Conclusion

By following the given equations and substituting the provided values, we have found that C10 = 387. If you have any further questions or need additional assistance, feel free to ask!