Question

Дано натуральное число n. Вычислить: S=1/1! - 1/2! - 1/3! -...- 1/n! Написать это в Паскале!

Answer 1

Calculating S=1/1! - 1/2! - 1/3! - ... - 1/n! in Pascal

To calculate the value of S=1/1! - 1/2! - 1/3! - ... - 1/n! in Pascal, you can use a simple loop to iterate through the values and calculate the sum. Here's a sample Pascal code to achieve this:

program CalculateS;
var
  n, i: integer;
  fact, sum: real;
begin
  write('Enter the value of n: ');
  readln(n);
  sum := 0;
  fact := 1;
  for i := 1 to n do
  begin
    fact := fact * i;
    sum := sum + 1 / fact;
  end;
  writeln('The value of S is: ', sum:0:2);
end.

In this Pascal program: 1. We declare variables for n, i, fact, and sum. 2. We prompt the user to enter the value of n. 3. We initialize sum to 0 and fact to 1. 4. We use a for loop to iterate through the values from 1 to n. 5. Inside the loop, we calculate the factorial and update the sum. 6. Finally, we display the value of S.

This program calculates the value of S=1/1! - 1/2! - 1/3! - ... - 1/n! for the given input value of n.

Note: The provided Pascal code calculates the value of S for the given input of n using a simple loop and factorial calculation.